Topic 1. Sample Mean, Variance, and Standard Deviation
Topic 2. Population and Sample Moments
Topic 3. Variance and Standard Deviation
Topic 4. Point Estimates and Estimators
Topic 5. Biased Estimators
Topic 6. Best Linear Unbiased Estimator
Q1. A risk manager gathers the following sample data to analyze annual returns for an asset: 12%, 25%, and –1%. He wants to compute the best unbiased estimator of the true population mean and standard deviation. The manager’s estimate of the standard deviation for this asset should be closest to:
A. 0.0111.
B. 0.0133.
C. 0.1054.
D. 0.1300.
Explanation: D is correct.
The calculations for the sample mean and sample variance are shown in the
following table
The sum of all observations of returns for the asset is 0.36. Dividing this by the number of observations, 3, results in an unbiased estimate of the mean of 0.12. The third column subtracts the mean from the actual return for each year. The last column squares these deviations from the mean. The sum of the squared deviations is equal to 0.338 and dividing this by 2, for an unbiased estimate (n – 1) instead of the number of observations, results in an estimated variance of
0.0169. The standard deviation is then 0.13 (computed as the square root of the variance).
Formula for sample variance:
Linear Estimators of the Mean: Computed as , where are weights (e.g., for equally likely observations), independent of
Q2. The sample mean is an unbiased estimator of the population mean because the:
A. sampling distribution of the sample mean is normal.
B. expected value of the sample mean is equal to the population mean.
C. sample mean provides a more accurate estimate of the population mean as the sample size increases.
D. sampling distribution of the sample mean has the smallest variance of any other unbiased estimators of the population mean.
Explanation: B is correct.
The sample mean is an unbiased estimator of the population mean, because the expected value of the sample mean is equal to the population mean. The best linear unbiased estimator (BLUE) is the best estimator of the population mean available because it has the minimum variance of any linear unbiased estimator.
Topic 1. Law of Large Numbers (LLN)
Topic 2. Central Limit Theorem (CLT)
Topic 3. Skewness
Topic 4. Kurtosis
Topic 5. Median and Quantile Estimates
Topic 6. Mean of Two Random Variables
Topic 7. Covariance and Correlation Between Random Variables
Topic 8. Coskewness
Topic 9. Cokurtosis
Q3. A junior analyst is assigned to estimate the first and second moments for an investment. Sample data was gathered that is assumed to represent the random data of the true population. Which of the following statements best describe the assumptions that are required to apply the central limit theorem (CLT) in estimating
moments of this data set?
A. Only the variance is finite.
B. Both the mean and variance are finite.
C. The random variables are normally distributed.
D. The mean is finite and the random variables are normally distributed.
Explanation: B is correct.
The CLT requires that the mean and variance are finite. The CLT does not require assumptions about the distribution of the random variables of the population.
Q4. A distribution of returns that has a greater percentage of extremely large deviations from the mean:
A. is positively skewed.
B. is a symmetric distribution.
C. has positive excess kurtosis.
D. has negative excess kurtosis.
Explanation: C is correct.
A distribution that has a greater percentage of extremely large deviations from the mean will be leptokurtic and will exhibit excess kurtosis (positive). The distribution will have fatter tails than a normal distribution.
Q5. The correlation of returns between Stocks A and B is 0.50. The covariance between these two securities is 0.0043, and the standard deviation of the return of Stock B is 26%. The variance of returns for Stock A is:
A. 0.0331.
B. 0.0011.
C. 0.2656.
D. 0.0112.
Explanation: B is correct.
Q6. Consider the following probability matrix:
The covariance between Stock A and B is closest to:
A. −0.160.
B. −0.055.
C. 0.004.
D. 0.020.
Explanation: B is correct.
The third cross central moment for pairs of random variables.
Dividing by the variance of one variable and the standard deviation of the other variable standardizes the cross third moment.
The two coskewness measures are computed as:
Measures the likelihood of large directional movements for one variable when the other variable is large.
Zero if there is no relationship between the sign of one variable and large moves in the other.
Always zero in a bivariate normal sample due to symmetrical and normal distribution.
We can estimate coskewness by applying an expectation operator as follows:
Q7. An analyst is graphing the cokurtosis and correlation for a pair of bivariate random variables that are normally distributed. For the symmetrical case of the three cokurtosis measures, k(X,X,Y,Y), cokurtosis is graphed on the y-axis and correlation is graphed on the x-axis between –1 and +1. The shape of this graph should be best described as a(n):
A. upward linear graph ranging in cokurtosis values between –3 and +3.
B. downward linear graph ranging in cokurtosis values between –1 and +1.
C. symmetrical curved graph with the maximum cokurtosis of 3 when the correlation is 0.
D. symmetrical curved graph with the minimum cokurtosis of 1 when the correlation is 0.
Explanation: D is correct.
A symmetrical curved graph with the minimum cokurtosis of 1 when the correlation is 0. The graph will be an upward sloping linear relationship for the other two asymmetric cases of cokurtosis k(X,Y,Y,Y) and k(X,X,X,Y).